Molar mass of LiBr ( lithium bromide ) = 86.845 g/mol
Amount of calculation to moles of lithium bromide (LiBr)
86.845 g ------------- 1 mole
100 g ----------------- ?
n = m / M
n = 100 / 86.845
n = 1.1514 moles of LiBr
V ---------------------1.1514 moles
1 L -------------------- 4 M
1.1514 * 1 / 4
V = 1151.4 / 4
V = 0,28785 L
hope this helps!
hope this helps !
