Respuesta :

carlosego
For this case we have the following vector:
 v = -6i.
 Using product point we have:
 v.v = (-6i.). (- 6i)
 v ^ 2 = 36
 Then, clearing the module we have:
 v = root (36)
 v = 6
 Answer:
 The module of the vector is given by:
 v = 6
 D. 6
mLawson8922

Answer:

D. 6

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