vanessakraemer1 vanessakraemer1
  • 23-05-2018
  • Mathematics
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5y^2 - 2y - 7 are (5y - 7) and ( )

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carlosego
carlosego carlosego
  • 23-05-2018
You have the following expression given in the problem above, which is a quadratic equation:

 5y^2 - 2y - 7=0

 When you factor the quadratic equation, you obtain the following form of it:
 (5y - 7)(y +1)=0

 Therefore, as you can see the answer is: (5y - 7)(y +1)=0
 
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