Answer:
Range is [0, π/2) ∪ [π/2, π)
Step-by-step explanation:
For the given function [tex]y=sec^{-1}x[/tex] if we draw a graph we find that it's discontinuous at x = -1 and 1.
Therefore domain of the function will be = (-∞, -1]∪[1, ∞)
and the range of the function will be [0, π/2) ∪ (π/2, π].
