JasonGD114 JasonGD114
  • 22-06-2018
  • Mathematics
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What are the x-intercepts of a parabola with a vertex of (-1,-16) and a y-intercept of (0,-15)?

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sqdancefan
sqdancefan sqdancefan
  • 22-06-2018
The vertex-form equation is
  y = a(x+1)² -16
Putting in the y-intercept values, we have
  -15 = a(0+1)² -16
  1 = a . . . . . . . . . . . add 16

Then the x-intercepts can be found where y=0.
  0 = (x+1)² -16
  16 = (x+1)²
  ±4 = x+1
  x = -1 ± 4 = {-5, 3}
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