Answer:
x+3z =7 is the equation of the plane.
Step-by-step explanation:
The line can be written as
[tex]\frac{x-6}{3} =\frac{y+1}{0} =\frac{z-1}{9} =t[/tex]
The line since perpendicular to the plane is normal to the plane.
Direction ratios of the line are (3,0,9)
SO plane has normal with DR (3,0,9) and plane passes through (7,-1,0)
3(x-7)+0(y+1)+9(z-0) =0
3x+9z =21
