Answer:
a = -4, b = 3 and c = 6 (OR)
a = -4, b = -3 and c = 6
Step-by-step explanation:
[tex]x^{2} +8x = 38[/tex]
Add 16 to both sides.
[tex]x^{2} +8x+16 = 38 + 16[/tex]
[tex](x+4)^{2} =54[/tex]
[tex]x + 4 = \sqrt{54}[/tex] or [tex]x + 4 = -\sqrt{54}[/tex]
[tex]x+4=3\sqrt{6}[/tex] or [tex]x+4=-3\sqrt{6}[/tex]
[tex]x=-4+3\sqrt{6}[/tex] or [tex]x=-4-3\sqrt{6}[/tex]
Therefore, a = -4, b = 3 and c = 6 (OR)
a = -4, b = -3 and c = 6
