bowenlucas1452 bowenlucas1452
  • 21-07-2018
  • Mathematics
contestada

Find the length and width of a rectangle whose perimeter is 40 feet and whose area is 96 square feet.

Respuesta :

ralphwx1 ralphwx1
  • 21-07-2018
Let the length and width be l and w, respectively. Then, perimeter = 2(l + w) = 40, and area = lw = 96. In other words:
l + w = 20
lw = 96
From here, we could guess and check to get that the length and width are 12 and 8, but let’s do this rigorously:
By the first equation, l = 20 - w
Substituting into the second equation:
(20 - w) * w = 96
w^2 - 20w + 96 = 0
w^2 - 20w + 100 = 4
(w - 10)^2 = 4
w - 10 = 2 or -2
w = 12 or 8
The rest is trivial.
Answer Link

Otras preguntas

Another easy question for Branilist....
so theyre are 1 in 1 box in box 3 in 3 box thank you hope you get it right!
how to breed a true blue flower
What is the total cost of a $44.55 meal at a restaurant after including a 17% tip? SHOW WORK!a. $27.55 c. $2.62b. $7.57 d. $52.12
I need to know the answer to this please help?
Identify and Explain the following: 10. Ways the monarchs of Austria and Russia used their absolute power 11. Peter the Great's legacy 12. Ways Catherine the Gr
Find the measure of an angle that cuts 3/10 of a circle​
How did European countries decide where to draw the new boundaries in Africa?
divide. will mark brainliest.​
what is the main reason why leaders created a supreme court