To solve this problem we must find 5% of 1418 and 4% of 1418
which is
[tex]5 \div 100 \times 1418 \\ \ \\ 4 \div 100 \times 1418[/tex]
so that would be 70.9 house extra in the first year and 56.72 extra in the second year respectively.
so to find the total number of houses we must add 70.9 + 56.72 + 1418 which gives us 1545.62
at the last it is mentioned for us to round our answer to the nearest
they are asking us for the total number whole number
which is 1546
so there would be 1546 houses in the second year.
