Perimeter of ABDE = 2+6+2+6 = 16
Perimeter of BCD:
Length BC = sqrt(3^2+4^2)=sqrt(9+16)=sqrt(25) = 5 [using Pythagoras]
Length CD = Length BC = 5
Length BD = 6
Perimeter of BCD = 5+5+6 = 16
=>
ratio of perimeters = 16:16 = 1:1
Area of figure
= area of rectangle + area of triangle
= 2*6 + 6*4/2
= 12+12
=24
