The line is parallel to y = 6/7 x - 5
The slope will be same .So equation of the line will be of the form:
[tex]y = \frac{6}{7} x + k \\[/tex]
It passes through C(1,5)
[tex]5 = \frac{6}{7} \times 1 + k \\ \\5 = \frac{6}{7} + k \\ \\ k = 5 - \frac{6}{7} \\ \\ k = \frac{7 \times 5 - 6}{7} = \frac{29}{7} [/tex]
[tex]line : \red{y = \frac{6}{7} x + \frac{29}{7} } \\ [/tex]
