Yuii
Yuii Yuii
  • 25-09-2018
  • Mathematics
contestada

PLEASE HELP ASAP!! CORRECT ANSWER ONLY PLEASE!!

Simplify.

i^99

PLEASE HELP ASAP CORRECT ANSWER ONLY PLEASE Simplify i99 class=

Respuesta :

tramserran
tramserran tramserran
  • 25-09-2018

i¹ = i

i² = -1

i³ = i * i²   = -i

i⁴ = i² * i²   = 1

Since i⁴ = 1, how many 4's can we pull out. (99 ÷ 4 = 24 with a remainder of 3).  Now, evaluate the remainder: i³ = -i

Answer: B

Answer Link
mkryukova19 mkryukova19
  • 25-09-2018

i¹ =1

i² = -1

i³=-1*i =-i

i⁴ = (-1)*(-1)= 1

99/4= 24  3/4

So, 99= 24*4 +3

i⁹⁹ = (i⁴)²⁴i³= 1²⁴i³ = i³ = -i

Answer is -i.

Answer Link

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