iwillrektyou
iwillrektyou iwillrektyou
  • 23-10-2018
  • Mathematics
contestada

Find the equation of the tangent line to the graph f(x) = x(1-2x)^3 at the point (1,-1)

Respuesta :

tramserran
tramserran tramserran
  • 23-10-2018

Answer: y = -4x + 4

Step-by-step explanation:

use the product formula (ab' + a'b) to find the derivative:

x * (1 - 2x)³

a = x             a' = 1

b = (1 - 2x)³   b' = 3(-2)(1 - 2x)²

                         = -6(1 - 2x)²

 ab' + a'b

= x(-6)(1 - 2x)² + 1(x)

= -6x(1 - 2x)² + x

Plug in the given x-values to find the slope:

= -6(1)(1 - 2(1))² + (1)

= -6(-1)² + 1

= -6 + 1

= -5

Next, input the slope and the point into the Point-Slope formula:

y + 1 = -5(x - 1)

y + 1 = -4x + 5

     y = -4x + 4


Answer Link

Otras preguntas

During the State of the Union address, the president is required to speak to A) the Supreme Court B) the vice president. C) governors in all fifty states. D) me
Prime factorization for 525 in expanded form
8.2 is 10% of what number
A Gardner has 27 pansies and 36 daisies. He plants an equal number of each type of flower in each row. What is the greatest possible number of pansies in each r
How much energy does it take to melt 225 g of ice (an amount about the size of a baseball) at 0oC?
Describe how the plasma membrane controls what goes into and comes out of a cell.
Paige moves 1/6 acre in 1/4 hour. how many acres does Paige mow per hour? Show work
Fractions: rules for adding neg & pos fractions 1/125-1/250= this confuses me?
what specific groups of americans made their way west in the 1800s
Before 1910,the most popular form of public entertainment was?