ANSWER
[tex]3.\bar4 =\frac{31}{9}[/tex]
EXPLANATION.
Let [tex]y=3.\bar4---(1)[/tex]
This is a recurring decimal. So we need to multiply by 10 to form a new equation that will cater for the recurring but when subtracted.
Multiply (1) by 10 to obtain,
[tex]10y=34.\bar4---(2)[/tex]
Equation (2) -equation (1) gives;
[tex]9y=31[/tex]
[tex]\Rightarrow y=\frac{31}{9}[/tex]
Hence the correct answer is A.
