The formula of a midpoint:
[tex]M\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)[/tex]
We have (3, 8) and (1, -4). Substitute:
[tex]\dfrac{3+1}{2}=\dfrac{4}{2}=2\\\\\dfrac{8+(-4)}{2}=\dfrac{4}{2}=2[/tex]
Hey there!!
Midpoint formula:
...[ (x₁+x₂)/2 , (y₁+y₂)/2 ]
Given:
... (3,8)(1,-4)
Inserting this into the midpoint formula:
... [(3+1)/2 , (8-4)/2]
... (4/2 , 4/2 )
... (2,2) is the midpoint
Hope my answer helps!
