Given equation is x+3y=27.
Now question says to find the x-intercept and y-intercept.
We know that x-intercept is the x-value when y=0
so plug y=0 into given equation and solve for x
x+3y=27
x+3*0=27
x+0=27
x=27
Hence x-intercept is at (27,0)
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We know that y-intercept is the y-value when x=0
so plug x=0 into given equation and solve for y
x+3y=27
0+3y=27
3y=27
y=9
Hence y-intercept is at (0,9)
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Hence final answer is the first choice
