Respuesta :

here we can say that net force on the student vertically upwards will be counter balance by his weight downwards

Let net force F is exerted by each hand

so here we will have

[tex]2Fcos15 = W[/tex]

[tex]2F cos15 = 800[/tex]

[tex]F = \frac{800}{2 cos15}[/tex]

[tex]F = 414.1 N[/tex]

so the force exerted by each hand will be 414.1 N

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