Answer:
see explanation
Step-by-step explanation:
combine the fractions on the left side into a single expression
I will use x instead of theta- I can't get it in the fraction
[tex]\frac{sin^2x+(1+cosx)^2}{sinx(1+cosx)}[/tex]
= [tex]\frac{sin^2x+1+2cosx+cos^2x}{sinx(1+cosx)}[/tex]
[ note that sin²x + cos²x = 1 ]
= [tex]\frac{2+2cosx}{sinx(1+cosx)}[/tex]
= [tex]\frac{2(1+cosx)}{sinx(1+cosx}[/tex]
= [tex]\frac{2}{sinx}[/tex]
= 2cscx = right side ⇒ verified
