Answer:
3 real solutions.
Step-by-step explanation:
Try x = 1 :
f(1) = 1 + 5 + 3 - 9 = 0
so x = 1 is a solution.
So x - 1 is a factor of the function.
If we divide the function by x - 1 we get the quotient x^2 + 6x + 9 which is
(x + 3)^2.
So there are 2 more roots of -3.
