Answer : The significant digit is 6
Explanation :
Multiply [tex]5.036\times10^{2}m[/tex] by [tex]0.078\times10^{-1}m[/tex]
Now, on multiplying
[tex]5.036\times10^{2}m \times0.078\times10^{-1}m = 0.392808 \times10^{1}\ m^{2}[/tex]
[tex]5.036\times10^{2}m \times0.078\times10^{-1}m = 0.0392808\ m^{2}[/tex]
Now, the significant digit is 6.
Hence, this is the required solution.
