taylors1mommie
taylors1mommie taylors1mommie
  • 22-02-2019
  • Mathematics
contestada

Find z1z2 if z1 = 2/5(cos63° + isin63°) and z2 = 10/3(cos117° + isin117°).

Respuesta :

AlonsoDehner AlonsoDehner
  • 22-02-2019

Answer:

-10/3 is the answer

Step-by-step explanation:

Given are two complex numbers as

[tex]z1=\frac{2}{5} (cos63  + isin63)\\z2=\frac{10}{3} (cos 117 + isin117})[/tex]

Recall Demoivre theorem as

(cosA+isinA)(cos A+isin B) = cos(A+B)+isin(A+B)

Hence here we have sum of angles  as

A+B = 63+117 =180

[tex]z1z2=\frac{2}{5} \frac{10}{3} (cos180+isin180)[/tex]

=[tex]\frac{-10}{3}[/tex]

Since sin180=0 and cos 180=-1

Answer Link
22nlin
22nlin 22nlin
  • 03-11-2020

Answer:

-4/3

Step-by-step explanation:

Took the quiz on odyssey ware and got it right

Answer Link

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