Respuesta :

sqdancefan

Answer:

(k·j)(x) = -12x^2 -x +6

Step-by-step explanation:

(k·j)(x) = k(x)·j(x) = (4x+3)(-3x+2) . . . . . substitute function definitions

  = 4·(-3)x^2 +(4·2+3(-3))x +3·2 . . . . . multiply using the distributive property

  = -12x^2 -x +6