Here is your answer
[tex]\bold {132} degrees [/tex]
REASON:
Given
m(arcAB)=45 degrees
/_ADB= 45
and, m(arcBE)= 87 degrees
/_BDE= 87
So,
/_ADE= /_ADB+/_BDE
/_ADE= 45+87
/_ADE= 132 degrees
HOPE IT IS USEFUL
