Respuesta :
If the square of a certain quantity must be 16, that quantity must be either 4 or -4.
In fact, in both cases we have [tex]4^2=(-4)^2=16[/tex]
So, we have two possible solutions:
[tex]x+1=4 \iff x=3[/tex]
[tex]x+1=-4 \iff x=-5[/tex]
Answer:
A. x= 3 or -5
Step-by-step explanation:
The solution is x = 3 or -5. The steps for solving the equation are shown.
(x + 1)2 = 16
(x + 1)2
= ±
16
x + 1 = ± 4
x + 1 = 4 or x + 1 = -4
x = 3 or -5
