jennn43 jennn43
  • 26-03-2019
  • Mathematics
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H20(l) > h20(g) calculate H rxn

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goodchandler
goodchandler goodchandler
  • 26-03-2019

H20 (liquid)- H20(gas)

The Enthalpy change for the above process can be written as:

ΔH=ΔHgas−ΔHliquid

and let us assume the claim in the question is right i.e

ΔHgas>ΔHliquid

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