Answer:
[tex]\large\boxed{D)\ \dfrac{8}{7}}[/tex]
Step-by-step explanation:
[tex]8\left(-\dfrac{2}{7}\right)\left(-\dfrac{1}{2}\right)\\\\\text{the product of two negative numbers is positive}\\\\8\cdot\dfrac{2\!\!\!\!\diagup^1}{7}\cdot\dfrac{1}{2\!\!\!\!\diagup_1}=8\cdot\dfrac{1}{7}\cdot\dfrac{1}{1}=\dfrac{8}{7}[/tex]
