Answer:
[tex]\large\boxed{x\leq1\dfrac{1}{5}}[/tex]
Step-by-step explanation:
[tex]\dfrac{2}{5}\geq x-\dfrac{4}{5}\qquad\text{add}\ \dfrac{4}{5}\ \text{to both sides}\\\\\dfrac{2}{5}+\dfrac{4}{5}\geq x-\dfrac{4}{5}+\dfrac{4}{5}\\\\\dfrac{2+4}{5}\geq x\\\\\dfrac{6}{5}\geq x\to x\leq\dfrac{6}{5}\\\\x\leq1\dfrac{1}{5}[/tex]
