Answer:
[tex]\large\boxed{m\angle R\approx76^o}[/tex]
Step-by-step explanation:
[tex]\dfrac{\sin R}{SQ}=\dfrac{\sin S}{RQ}\\\\\text{We have:}\\\\SQ=32,\ RQ=26,\ S=52^o\to\sin52^o\approx0.788\\\\\text{Substitute:}\\\\\dfrac{\sin R}{32}=\dfrac{0.788}{26}\qquad\text{multiply both sides by 32}\\\\\sin R\approx0.97\to R=\arcsin(0.97)\\\\R\approx76^o[/tex]
