area of lateral surface
Area=0.5bh×4(because there are four lateral faces)
b=12m
Area=0.5×12m×h
Area=6m×h
using Pythagoras theorem to find height of the triangle of lateral surface.
h²=6²+H²(height of the pyramid)
h²=6²+6²
h²=36+36
h²=72
h=root of 72
h=8.5cm(rounded to nearest tenth)
SA=6m×8.5m×4
Sa=51m²×4
Sa=201m²
answer.. 204m²
