ANSWER
[tex]\frac{ {y}^{2} }{49} + \frac{ {x}^{2} }{ 16 } = 1[/tex]
EXPLANATION
The given ellipse has a vertex at (0, -7), a co-vertex at (4,0), and a center at the origin.
The equation of an ellipse with vertex on the y-axis and center at the origin is given by
[tex]\frac{ {y}^{2} }{a ^{2} } + \frac{ {x}^{2} }{ {b}^{2} } = 1[/tex]
[tex]\frac{ {y}^{2} }{( - 7) ^{2} } + \frac{ {x}^{2} }{ {4}^{2} } = 1[/tex]
[tex]\frac{ {y}^{2} }{49} + \frac{ {x}^{2} }{ 16 } = 1[/tex]
