using factoring by grouping:
(x^3 + x^2) + (9x + 0)
x^2(x+1) + 9(x+1)
(x^2+9)(x+1)
Answer: (x+1)(x² + 9)
Step-by-step explanation:
Let f(x)=x³ + x² + 9x + 9
let x= -1
f(-1) = (-1)³ +(-1)² + 9(-1) + 9
= -1 +1 -9 +9 =0
Therefore, (x+1) is a factor
we now divide x³ + x² + 9x + 9 by x+1
x² + 9
_________
x+ 1√x³ + x² + 9x +9
- (x³ + x²)
______________
9x + 9
- (9x +9)
_______________
0
Therefore, (x+1) and (x² + 9) are the 2 factors of the polynomial.
