Answer:
(9, -2) and (0, 4)
Step-by-step explanation:
[tex]2x+3y=12\\\\(9,\ y)\to\text{put x = 9 to the equation of a line:}\\\\2(9)+3y=12\\18+3y=12\qquad\text{subtract 18 from both sides}\\3y=-6\qquad\text{divide both sides by 3}\\y=-2\\\boxed{(9,\ -2)}\\\\(x,\ 4)\to\text{put y = 4 to the equation of a line:}\\\\2x+3(4)=12\\2x+12=12\qquad\text{subtract 12 from both sides}\\2x=0\qquad\text{divide both sides by 2}\\x=0\\\boxed{(0,\ 4)}[/tex]
