makaylab147 makaylab147
  • 22-07-2019
  • Mathematics
contestada

verify that (sinx -cosx)^2=1-2sin(x)cos(x)

Respuesta :

abdo2001 abdo2001
  • 22-07-2019

(sinx - cosx)^2 = (sinx)^2 + (cosx)^2 - 2sinxcosx = 1-2sinxcosx

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Аноним Аноним
  • 22-07-2019

Answer:

See below.

Step-by-step explanation:

Left side =  (sinx -cosx)^2 = sin^2 x + cos^2x - 2sinx cosx

Now sin^2 x + cos^2 x = 1 so we have:

1 - 2 sinx cosx = right side.

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