Answer:
[tex]\large\boxed{\pm\dfrac{5}{2}=\pm2.5}[/tex]
Step-by-step explanation:
[tex]\sqrt{a}=b\iff b^2=a\\\\\pm\sqrt\dfrac{25}{4}}\qquad\text{use}\ \sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}\\\\=\pm\dfrac{\sqrt{25}}{\sqrt{4}}=\pm\dfrac{5}{2}=\pm2.5\\\\\text{because}\\\\\left(\dfrac{5}{2}\right)^2=\dfrac{25}{4}\ \text{and}\ \left(-\dfrac{5}{2}\right)^2=\dfrac{25}{4}[/tex]
