Answer:
[tex]2x+y[/tex]
Step-by-step explanation:
we have
[tex]\frac{1}{3}(12x+6y)-\frac{1}{6}(12x+6y)[/tex]
Factor the term (12x+6y)
[tex](12x+6y)[\frac{1}{3}-\frac{1}{6}][/tex]
Remember that
[tex]\frac{1}{3}=\frac{2}{6}[/tex]
substitute
[tex](12x+6y)[\frac{2}{6}-\frac{1}{6}][/tex]
[tex](12x+6y)\frac{1}{6}[/tex]
Applying distributive property
[tex]\frac{12}{6}x+\frac{6}{6}y[/tex]
Simplify
[tex]2x+y[/tex]
