Respuesta :

whiskeyo
[tex] (\sqrt[3]{x^{2}})^{6}=x^{(2* \frac{1}{3})*6}=x^{ \frac{2}{3}*6 } =x^{4}[/tex]
charstar
the cube root of x^2 is x^2/3
because it is in the bracket and the power of 6 sign is outside you multiply its index (2/3) by 6 and you have x^4
so the answer is the second one, x^4

hope this helps :)

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