Answer:
[tex]density=4.91g/L=4.91x10^{-3}g/mL[/tex]
Explanation:
Hello,
Ideal gas equation is useful in this case because one could solve for density as follows:
[tex]PV=nRT\\\frac{n}{V}=\frac{P}{RT} \\\frac{m}{MV}=\frac{P}{RT} \\\frac{m}{V}=\frac{PM}{RT} \\\ density=\frac{PM}{RT}[/tex]
Now, replacing for P and T, one obtains:
[tex]density=\frac{742mmHg*\frac{1atm}{760mmHg}*131.293g/mol}{0.082\frac{atm*L}{mol*K} (45+273.15)K}\\\\density=4.91g/L=4.91x10^{-3}g/mL[/tex]
Best regards.
