Answer:
Answered.
Step-by-step explanation:
let the equation be
y= x^2-6x+10
y= x^2-6x+9+1
(y-1)= (x-3)^2
comparing it with standard equation of a parabola
y=4x^2, clearly both will be facing upward
has vertex (0,0) where as the parabola (y-1)= (x-3)^2 has vertex as (3,1)
clearly it will not cut the x- axis and hence it will not have any real roots.
moreover, Mathematically x²-6x+10=0 on solving has roots 3-i and 3+i
