Answer:
Given :
[tex]3\times(10)^{-x} = \frac{1}{9}[/tex]
Therefore, taking log on both sides we get:
[tex]log(3\times(10)^{-x}) = log(\frac{1}{9})[/tex]
[tex]log(3) - x\times log(10) = log(1) - log(9)[/tex]
Now, equating the values of the above variables we get:
0.4771 - x(1) = 0 - 0.9542
x = 0.4771 + 0.9542
x = 1.4313
