evanpappas0401 evanpappas0401

22-10-2019
Mathematics

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how many gallons of a 70% antifreeze solution must be mixed with 80 gallons of 25% antifreeze to get a mixture that is 60% antifreeze?

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yamilacarranza yamilacarranza

22-10-2019

Answer:m(.70)+80(.25)=.6(m+80)

.7m+20=.6m+48

.1m=28

m=28/.1=280 gallons of 25% antifreeze needed

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