tiffanyhulsey tiffanyhulsey
  • 23-10-2019
  • Mathematics
contestada

Evaluate y=x squared minus 2x plus one for 3i

Respuesta :

kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 24-10-2019

Answer:

[tex] - 8 - 6i[/tex]

Step-by-step explanation:

The given expresion is

[tex]y = {x}^{2} - 2x + 1[/tex]

We want to evaluate this expression when x=3i

We substitute to obtain:

[tex]y = {(3i)}^{2} - 2(3i) + 1[/tex]

We simplify to get

[tex]y = {3}^{2} \times {i}^{2} - 6i + 1[/tex]

Recall that

[tex] {i}^{2} = - 1[/tex]

This implies that:

[tex]y = 9 \times - 1 - 6i + 1[/tex]

[tex]y = - 9 - 6i + 1[/tex]

[tex]y = - 8 - 6i[/tex]

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