Answer:
2(r + 6)(r + 2)
Step-by-step explanation:
Given
2r² + 16r + 24 ← factor out the common factor 2 from each term
= 2(r² + 8r + 12)
Consider the factors of the constant term (+ 12) which sum to give the coefficient of the r- term (+ 8)
The factors are + 6 and + 2, thus
r² + 8r + 12 = (r + 6)(r + 2) and
2r² + 16r + 24 = 2(r + 6)(r + 2) ← in factored form
