Two oppositely charged parallel sheets of charge give rise to a field of 9.00×1011 N/C between them. The sheets are square and have dimensions 0.85m×0.85m. Assume that the charge distribution and electric field are uniform, as if the sheets were infinite in size, and that the distance between the sheets is much smaller than 0.85m. How much charge must there be on each sheet?

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aristocles aristocles · Answer 1 · 2019-10-24T05:47:04+02:00

Answer:

[tex]Q = 5.75 C[/tex]

Explanation:

As we know that due to a thin sheet electric field at a point near its surface is given as

[tex]E = \frac{\sigma}{2\epsilon_0}[/tex]

now we have two sheets of opposite charges so the net electric field is double that of field due to one sheet

so we have

[tex]E_{net} = 2E[/tex]

[tex]E_{net} = \frac{\sigma}{\epsilon_0}[/tex]

[tex]9.00 \times 10^{11} = \frac{Q}{A\epsilon_0}[/tex]

now we have

[tex]Q = 9.00 \times 10^{11}(0.85 \times 0.85)(8.85 \times 10^{-12})[/tex]

[tex]Q = 5.75 C[/tex]