Answer: [tex]n^3[/tex], where n = 1,2,3,4,.....
Step-by-step explanation:
The given sequence : 1, 8, 27, 64, ….
We observe that the terms are perfect cubes of consecutive integers (starting from 1) .
Terms can be written as:
First term = [tex]a_1=1=1^3[/tex]
Second term=[tex]a_2=8=2^3[/tex]
Third term = [tex]a_3=27=3^3[/tex]
Fourth term =[tex]a_4=64=4^3[/tex]
Thus , for any nth term ,the formula for the sequence is : [tex]n^3[/tex], where n = 1,2,3,4,.....
