Answer:
18.75 mL of NaCl solution is required.
Explanation:
Given data:
Molarity of solution one = 2.0 M
Volume of solution one = ?
Molarity of second solution = 0.15 M
Volume of second solution = 250 mL
Solution:
M₁V₁ = M₂V₂
V₁ = M₂V₂/M₁
V₁ = 0.15 M × 250 mL / 2.0 M
V₁ = 37.5 M.mL / 2.0 M
V₁ = 18.75 mL
