Answer:
The option A and C are correct that is
[tex]-3(x - 8)\\\ \frac{3}{2}(-2x +16)[/tex]
Step-by-step explanation:
Given:
[tex]-3x + 24 \\ \textrm {is quivalent to}\\-3(x - 8) = -3x --3\times8 = -3x + 24\\\\\frac{3}{2}(-2x + 16) = \frac{3}{2}\times-2x + \frac{3}{2}\times 16 = -3x + 24[/tex]
Therefore, The option A and C are correct that is
[tex]-3(x - 8)\\\ \frac{3}{2}(-2x +16)[/tex]
