Answer:
±11.18
Step-by-step explanation:
the function is:
[tex]f(q)=q^2-125[/tex]
and to find the roots we need to find which values of [tex]q[/tex] makes the function result in zero:
[tex]q^2-125=0[/tex]
solving for [tex]q[/tex]:
[tex]q^2=125\\q=\sqrt{125}[/tex]
A square root has two solutions, one positive and one negative, so the solutions are:
[tex]q=[/tex]±[tex]\sqrt{125}[/tex] ≈ ±11.18
the roots of the quadratic equation are +11.18 and -11.18
