Answer:
[tex]v=\sqrt{\frac{2GMh}{R^{2}}}[/tex]
Explanation:
mass of object = m
Mass of planet = M
Radius of planet = R
Height = h
Let the speed of the object as it hits the earth's surface is v.
the value of acceleration due to gravity
g = G M / R^2
where, g is the universal gravitational constant.
Use third equation of motion
[tex]v^{2}=u^{2}+2gh[/tex]
where, u is the initial velocity which is equal to zero.
So, [tex]v^{2}=0 + 2 \times \frac{GM}{R^{2}}\times h[/tex]
[tex]v=\sqrt{\frac{2GMh}{R^{2}}}[/tex]
