Answer:
[tex]f^{-1} (x)=9x+18[/tex]
Step-by-step explanation:
Assuming [tex]f(x)=\frac{1}{9} x-2[/tex]
What we have to do is replace f(x) with y, swap the locations of x and y, and then solve for y.
[tex]y= \frac{1}{9} x-2\\\\x=\frac{1}{9}y-2\\ \\x+2=\frac{1}{9}y\\\\y=9x+18\\\\f^{-1} (x)=9x+18[/tex]
