Answer:
[tex]g(0)=4\\g(2)=3\\g(5)=-\frac{17}{2}[/tex]
Step-by-step explanation:
[tex]g(x)=\{-\frac{1}{2}x^2+4 \ \ \ if \ x\not=2\\g(x)=\{3 \ \ \ if \ x=2\\ \\g(0)=-\frac{1}{2}\times 0+4=4\\\\g(2)=3 \ \ \ (given)\\\\g(5)=-\frac{1}{2}(5)^2+4\\\\=\frac{-25}{2}+4\\\\=\frac{-17}{2}[/tex]
